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5y^2-32y+35=0
a = 5; b = -32; c = +35;
Δ = b2-4ac
Δ = -322-4·5·35
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-18}{2*5}=\frac{14}{10} =1+2/5 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+18}{2*5}=\frac{50}{10} =5 $
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